The Next Greater Number of a number x in nums1 is the first greater number to its right in nums2. The Next Greater Number of a number x in nums1 is the first greater number to its right in nums2. Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. LeetCode; Introduction Easy 13. The Next Greater Number of a number x is the first greater number to its traversing-order next in the array, which means you could search circularly to find its next greater number. The Next Greater Number of a number x in nums1 is the first greater number to its right in nums2. Fizz Buzz 415. If it doesn't exist, output -1 for this number. Convert a Number to Hexadecimal 409. If it does not exist, output -1 for this number. IV) Now sort all digits from position next to ‘d’ to the end of number. Let’s number the nodes in the list: node_1, node_2, node_3, … etc. The Next Greater Number of a number x in nums1 is the first greater number to its right in nums2. Example 1: Input: nums1 = [4,1,2], nums2 = [1,3,4,2]. If it doesn't exist, output -1 for this number. If it does not exist, output -1 for this number. If it does not exist, output -1 for this number. The Next Greater Number of a number x is the first greater number to its traversing-order next in the array, which means you could search circularly to find its next greater number. Find all the next greater numbers for nums1‘s elements in the corresponding places of nums2. Example 1: Input: nums1 = [4,1,2], nums2 = [1,3,4,2]. Example 1: Example 1: Input: nums1 = [4,1,2], nums2 = [1,3,4,2]. If it doesn’t exist, output -1 for this number. Add Strings 437. For “534976″, the right side of 4 contains “976”.The smallest digit greater than 4 is 6.. III) Swap the above found two digits, we get 536974 in above example. Next Greater Element III Medium Given a positive 32-bit integer n , you need to find the smallest 32-bit integer which has exactly the same digits existing in the integer n and is greater in value than n. Path Sum III 447. Output: [-1,3,-1] Explanation: For number 4 in the first array, you cannot find the next greater number for it in the second array, so output -1. Roman to Integer ... 405. If it does not exist, output -1 for this number. Output: [-1,3,-1] Explanation: For number 4 in the first array, you cannot find the next greater number for it in the second array, so output -1. The Next Greater Number of a number x is the first greater number to its traversing-order next in the array, which means you could search circularly to find its next greater number. We are given a linked list with head as the first node. The Next Greater Number of a number x in nums1 is the first greater number to its right in nums2. The number that we get after sorting is the output. II) Now search the right side of above found digit ‘d’ for the smallest digit greater than ‘d’. Example 1: Input: nums1 = [4,1,2], nums2 = [1,3,4,2]. If it does not exist, output -1 for this number. Find all the next greater numbers for nums1 's elements in the corresponding places of nums2. Each node may have a next larger value: for node_i, next_larger(node_i) is the node_j.val such that j > i, node_j.val > node_i.val, and j … Stack. Longest Palindrome 412. Output: [-1,3,-1] Explanation: For number 4 in the first array, you cannot find the next greater number for it in the second array, so output -1. Output: [-1,3,-1] Explanation: For number 4 in the first array, you cannot find the next greater number for it in the second array, so output -1. If it does not exist, output -1 for this number. The Next Greater Number of a number x in nums1 is the first greater number to its right in nums2. Medium. Example 1: